Question

from the quadratic polynomial whose zeroes are b) -√2 and √2​

Answer 1

Answer:

$x^{2}-2$

Step-by-step explanation:

$x=-\sqrt{2} \\x=\sqrt{2}\\\\=(x+\sqrt{2})(x-\sqrt{2})\\(a+b)(a-b)=a^{2}-b^{2}\\=x^{2}-(\sqrt{2})^{2}\\=x^{2}-2$