From the reaction N2 + 3H₂ =2NH3 ; d(NH3)/dt= 4x10⁴mol dm³s¹.What is the rate of decomposition of N2?
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Explanation:
of -d[H_2]dt would be:
Missing: 4x10⁴mol dm³s¹.
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N2 + 3H2⟶2NH3 Applying rate law. -13 d [H2 ]dt = 12 d [NH3 ]dt Now, given that d [NH3 ]dt = 2 × 10^-4mol L^-1S^-1 Using above relation, -d [H2 ]dt ...
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