From the rifle of mass 4 kg , a bullet of mass 50 gm is fired with initial velocity of 35m/s . The initial velocity of the gun is
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Hi friend here is your answer
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We know from conservation of momentum,
MV=mv
Where m=mass of the bullet
v= velocity of the bullet
M=Mass of the gun
V=velocity of the gun
Before solving , convert 50gm into kg
50gm=50 ×10^-3 kg=5×10^-2 kg=0.05 kg
So 4×V=0.05×35
V=1.75/4=0.4375 m/s.
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*****************************************
We know from conservation of momentum,
MV=mv
Where m=mass of the bullet
v= velocity of the bullet
M=Mass of the gun
V=velocity of the gun
Before solving , convert 50gm into kg
50gm=50 ×10^-3 kg=5×10^-2 kg=0.05 kg
So 4×V=0.05×35
V=1.75/4=0.4375 m/s.
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charmisha:
What is it
I did not get , but answer must be in these options a)0.50 m/s b)0.40 m/s c)0.48 m/s d)0.44m/s
Thanks
Answered by
0
Dear Friend. This will help you.
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the Answer is 0.44 m/s.
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