From the same place at 7 am A started walking in the north at the speed of 5km/hr.After one hour B started cycling in the east at a speed of 16km/hr.At what time they will be at a distance of 52 km apart from each other?
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THEREFORE.
AT 11am A & B are 52km apart from each other.
HOPE THIS HELPS YOU!!!
AT 11am A & B are 52km apart from each other.
HOPE THIS HELPS YOU!!!
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They will be at a distance of 52km between them at 11 AM
Let t = time in hrs for the walker to be 52 km from the cyclist
(t-1) = time for the cyclist to be 52km from the walker
5t = the distance walked
16(t-1) = distance cycled
, this can also be written as (16t-16)
Since the 2 people are walking towards North and East, we can use Pythagoras theorem as the angle between them is 90 degrees.
(5t)^2 + (16t-16)^2 = 52^2
25t^2+256t^2-512t+256 = 2704
281t^2 -512t-2448=0
t=4 hours. Hence, they will be at a distance of 52 km at (7+4)=11 AM
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