From the same point, two balls A and B are thrown simultaneously. A is thrown vertically up with a velocity of 20 m/s. B is thrown with a velocity of 20 m/s at an angle of 60° with the vertical. Determine the separation between the two balls at t=1s
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Answer:
Watch the explanation....
Explanation:
At first... the position of A is vertically up.....
so, h= 15.1m
Now for the B, we get position in x component at time to 1 .....
here the B is angled 60° with y component and 30° with x component.
so, x = 10root3 m.
Now, for y component we get.....
and, y = 5.1 m
Now the horizontal distance between A and B is 10root3 or 17.3m
The vertical distance between A and B is 10 m
And the all round displacement is.....
which is about (correctly to say..) 20 m.
I am done.
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