Question

From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9,​

Answer 1

Answer:

$\frac{2}{5}$

Step-by-step explanation:

${ \small{ \textsf{ \purple{total \: numbers - - }}}}$

10

${ \small{ \orange{ \textsf{numbers \: which \: make \: sum \: 9}}}}$

4

how ???

1+8= 9

3+6=9

4+5=9

7+2=9

${ \green{ \textsf{probability - }}} \\ \frac{favourable \: \: outcome}{total \: \: outcomes}$

$\frac{4}{10} \\ = \frac{2}{5}$

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@ Lalitya