Math, asked by AShh3436, 1 year ago

From the side pq of triangle pqr,cut off line segment pl=qs.draw lm // qr and st // pr.shiw that mt//pq

Answers

Answered by amitnrw
12

Answer:

MT ║ PQ

Step-by-step explanation:

LM ║ QR

=> ΔPLM ≈ ΔPQR

=> PL/PQ = PM/PR

ST ║ PR

=> Δ QST ≈ ΔQPR

=> QS/PQ  = QT/QR

QS = PL

=> PL/PQ = QT/QR

PL/PQ = PM/PR  &  PL/PQ = QT/QR

=> PM/PR = QT/QR

=> 1 - PM/PR = 1  - QT/QR

=> (PR - PM)/PR = (QR - QT)/QR

=> RM /PR  = RT / QR

in Δ RMT  & ΔRPQ

∠R is common

&  RM /PR  = RT / QR

=>  Δ RMT  ≈ ΔRPQ

=> MT ║ PQ

Answered by manshas
13

Answer:

hope this helps u

Step-by-step explanation:

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