from the solid circular cylinder with height 10 cm and radius of base is 6 CM a right circular cone of the same height and same base is removed find the volume of the remaining solid
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Step-by-step explanation:
TSA of remaining solid = TSA of cylinder - TSA of cone
= 2πr(r+h) - πr(r+l)
= πr(2r + 2h - r + l)
=22 / 7 × 6 ( 20+6+11.66)
=22 / 7 × 6 × 37.66
=710.16cm^2
volume of remaining solid = Volume of Cylinder - volume of cone
=πr^2h - 1/3πr^2h
=2 /3πr^2h
=2 /3×22 /7×6×6×10
=753.6cm^3
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sudhanshu96:
thanks for this answer
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