From the stake in the ground the angle of elevation of the connection with the tree is 42º. Find to the nearest tenth of a foot, the height of the connection point on the tree.
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Answer:
Step-by-step explanation:
tan45
o
=
BC
AC
1=
BC
80
BC=80cm
tan30
o
=
BC+CE
DE
3
1
=
80+x
80
80+x=80
3
x=80
3
−80
x=80(
3
−1)m
The bird travelled 80(
3
−1)m
Speed of bird =
Time
Distance
=
2
40(
3
−1)
=40(
3
−1)m/s
∴ Speed =40(
3
−1)m/
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