Question

from the start point on the Runway to finally take off an aircraft takes 50 seconds. during this period it covers a distance of 1 kilometre what is the accelaration during take off?

Answer 1

a = (v-u)/t

t= 50 s
v= 1000m/ 50 s = 20 m/s
u= 0 m/s

a = (20 - 0)/5 m/s^2 = 4 m/s^2

Answer 2

Its acceleration during the take off is $0.8\ m/s^2$.

Explanation:

It is given that, from the start point on the Runway to finally take off an aircraft takes 50 seconds,

It covers a distance of 1 km or 1000 m during this period.

We need to find the acceleration during take off.

Using equation of motion as :

$s=ut+\dfrac{1}{2}at^2$

u = 0 here

$s=\dfrac{1}{2}at^2\\\\a=\dfrac{2s}{t^2}\\\\a=\dfrac{2\times 1000}{(50)^2}\\\\a=0.8\ m/s^2$

So, its acceleration during the take off is $0.8\ m/s^2$.

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Kinematics

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