Question

From the string of a sonometer a constant weight is suspended. The resonating length of the string is noted as 50 cm for tuning fork of 200 hz. If a tuning fork of 250 hz is used, what should be the distance between the two knife edges to get resonance?

Answer 1

use the formula dear 250/50= 5 cm

Answer 2

Explanation:

u1/u2=l2/l1.

bcoz L is inversely proportional to frequency.

u1×u2/l1=l2

200×50/250=40cm

ans.is 40cm.

and u=neu.