Question

From the structures given below, Tabulate the following:
1. Valence electron
2. Valency
3. Atomic Number
4. Mass number
5. Electronic configuration

Answer 1

Atomic no.. 6..12...17...20..19..13.
Atomic mass... 12...24....35...40....39...27
EC
1S2 2s2 2p2
1s2 2s2 2p6 3s2
1s2 2s2 2p6 3s2 3p5
1s2 2s2 2p6 3s2 3p6 4s2
1s2 2s2 2p6 3s2 3p6 4s1
1s2 2s2 2p6 3s2 3p1
ValencY +2...0.... - 1...0...+1...+1


I only knows this.... Hope it helps

Answer 2

1. no of protons = 6 , no of neutrons = 6

1. Valence electron = 4
2. valency = 4
3. atomic number = no of protons = 6
4. mass number = no of protons + no of neutrons = 6 + 6 = 12
5. electric configuration = 2, 4

2. no of protons = 12 , no of neutrons = 12

1. Valence electron = 2
2. valency = 2
3. atomic number = no of protons = 12
4. mass number = no of protons + no of neutrons = 12 + 12 = 24
5. electric configuration = 2 , 8, 2

3. no of protons = 17 , no of neutrons = 18

1. Valence electron = 7
2. valency = 1
3. atomic number = no of protons = 17
4. mass number = no of protons + no of neutrons = 17 + 18 = 35
5. electric configuration = 2, 8, 7

4. no of protons = 20 , no of neutrons = 20

Valence electron = 2

valency = 2

atomic number = no of protons = 20

mass number = no of protons + no of neutrons = 20 + 20 = 40

electric configuration = 2, 8, 8, 2

5.no of protons = 19 , no of neutrons = 20

Valence electron = 1

valency = 1

atomic number = no of protons = 19

mass number = no of protons + no of neutrons = 19 + 20 = 39

electric configuration = 2, 8, 8, 1

6. no of protons = 13 , no of neutrons = 14

Valence electron = 3

valency = 3

atomic number = no of protons = 13

mass number = no of protons + no of neutrons = 13 + 14 = 27

electric configuration = 2, 8, 3