Math, asked by alonaroy57, 5 hours ago

from the sum 2y^2 +3yz , -y^2 -yz -z^2 n yz +2z2 , subtract the sum of 3y^2-z^2 and -y+yz+z^2. plsss write it in a paper , step by step explaination I will mark u as brainlist​

Answers

Answered by debarghyaray53
1

Step-by-step explanation:

from the sum 2y^2 +3yz , -y^2 -yz -z^2 n yz +2z2 , subtract the sum of 3y^2-z^2 and -y+yz+z^2. plsss write it in a paper , step by step explaination I will mark u as brainlist

Answered by sonumondithoka
0

Step-by-step explanation:

Sum of 2y

2

+3yz,−y

2

−yz−z

2

and yz−2z

2

=2y

2

+3yz−y

2

−yz−z

2

+yz+2z

2

=y

2

+z

2

+3yz

And sum =3y

2

−z

2

,(−y

2

+yz+z

2

)

=3y

2

−z

2

−y

2

+yz+z

2

=2y

2

+yz

We need to find:

(y

2

+z

2

+3yz)−(2y

2

+yz)

=y

2

+z

2

+3yz−2y

2

−yz

=−y

2

+z

2

+2yz

=−y

2

+2yz+z

2

please mark me brainliests

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