from the sum of 11 p³ - 3q² and 4 p³ + 6 q² , subtract the sum of 9 p³ + q² and 3 p³ - 4q²
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2
Answer:
ab+2b
2
+3b
2
−a
2
)−((12ab−10b
2
−18a
2
)+(9ab+12b
2
+14a
2
))
(ab+2b
2
+3b
2
−a
2
)−(21ab+2b
2
−4a
2
)
(ab+2b
2
+3b
2
−a
2
)−21ab−2b
2
+4a
2
(ab+5b
2
−a
2
)−21ab−2b
2
+4a
2
=3b
2
+3a
2
−20ab
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