Question

From the sum of 11a³-8b² and 4a³+6b²subtract the sum of 9a³+b²and 3a³-4b²​

Answer 1

Question:

$= > ((11 {a}^{3} - 8 {b}^{2} ) + (4 {a}^{3} + 6 {b}^{2} )) - ((9 {a}^{3} + {b}^{2} ) + (3 {a}^{3} - 4 {b}^{2} ))$

Answer:

$= > ((11 {a}^{3} - 8 {b}^{2} ) + (4 {a}^{3} + 6 {b}^{2} )) - ((9 {a}^{3} + {b}^{2} ) + (3 {a}^{3} - 4 {b}^{2} ))$

$= > ((15 {a}^{3} - 2 {b}^{2} ) - (12 {a}^{ 3} - 3 {b}^{2} ))$

$= > 3 {a}^{3} + {b}^{2}$

Hope this answer helps you ^_^ !

Answer 2

Step-by-step explanation:

Hope it helps....