Question

From the sum of 11x³– 3y²+8 and 2x³+12y²–1, subtract the sum of 9x³+y²–1 and 3x²+3y²+18

Answer 1

Answer:

Your answer is....

{(11x³-3y²+8)+(2x³+12y²-1)} - {(9x³+y²-1)+(3x³+3y²+18)

= (11x³-3y²+8+2x³+12y²-1) - (9x³+y²-1+3x³+3y²+18)

= (13x³+9y²+7) - (12x³+4y²+17)

= 13x³+9y²+7-12x³-4y²-17

= x³+5y²-10

Your answer is...x³+5y²-10

Step-by-step explanation:

Hope it will help you.

Please give a thanks and mark as brainliest.