Question

From the sum of 12a + 5b – 15c and -5a +4c –b, subtract 9b +4c.​

Answer 1

Answer:

3c

Step-by-step explanation:

3a+4b+7c,−5a+3b−6c and 4a−2b−4c

The sum of 3a+4b+7c,−5a+3b−6c and 4a−2b−4c is calculated as shown below

(3a+4b+7c)+(−5a+3b−6c)+(4a−2b−4c)

=3a+4a−5a+4b+3b−2b+7c−6c−4c

We get,

=2a+5b−3c

Hence, the sum of 3a+4b+7c,−5a+3b−6c and 4a−2b−4c is 3c

Answer 2

A.T.Q:

{(12a + 5b - 15c) + (-5a + 4c - b)} - 9b + 4c

Opening inner-most brackets:

{12a - 5a + 5b - b - 15c + 5c} - 9b + 4c

Solving

{7a + 4b - 10c} - 9b + 4c

Opening brackets again

7a + 4b - 9b -10c + 4c

7a -5b -6c

So, the answer is 7a -5b -6c.

Hope this Helped! ヾ(•ω•`)o