From the sum of 13a + 19b + 12c and 14a - 21b + 11c, subtract the sum of 17a + 13b - 15c and
8a + 12b - 18c.
Answers
hey mate,
your question.
From the sum of 13a + 19b + 12c and 14a - 21b + 11c, subtract the sum of 17a + 13b - 15c and
8a + 12b - 18c.
Step-by-step explanation:
First set,
\displaystyle\sf{(13a+19b+12c)+(14a-21b+11c)
=\displaystyle\sf{13a+19b+12c+14a-21b+11c
=\sf{27a-2b+23c
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Second set,
\sf{(17a+13b-15c)+(8a+12b-18c)
=\sf{17a+13b-15c+8a+12b-18c
=\sf{25a+25b-33c
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First set - Second set,
\sf{(27a-2b+23c)-(25a+25b-33c)
=\sf{27a-2b+23c-25a+25b-33c
=\sf{2a+23b-10c
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\boxed{\bold{\displaystyle\sf{Answer=2a+23b-10c}}}
Answer=2a+23b−10c
I HOPE IT HELP YOU...
HAVE A AWESOME DAY WITH FUN AND LEARN...
Answer:
2a+23b-10c
Step-by-step explanation:
1step
13a + 19 b + 12c+ 14 a - 21 b + 11 c
= 27a - 2b + 23c
2step
17 a + 13 b - 15 c + 8a+ 12 b - 18c
=25a+ 25 b - 33 c
last step
27a - 2 b + 23c - 25a+ 25b - 33c
= 2a+ 23b - 10 C