Question

From the sum of 14 a + 9b -8c and 12b +13c -15a , subtract the sum of 8a -17b + 4c and 11a -16b + 17c.

Answer 1

hope it helps you

please refer to attachment

how??

first find the sum of both equation

and know subtract them

sum:

(14a+9b-8c) + (12b+13c-15a)

14a+9b-8c+12b+13c-15a

14a-15a+9b+12b-8c+13c

-1a+21b+5c

(8a-17b+4c) + (11a-16b+17c)

8a-17b+4c+11a-16b+17c

8a+11a-17b-16b+4c+17c

19a-33b+21c

subtract:

(19a-33b+21c) - (-1a+21b+5c)

19a-33b+21c+1a+21b+5c

19a+1a-33b+21b+21c+5c

20a-12b+26c

final answer:

20a-12b+26c

Answer 2

Given: The equations are $14 a + 9b -8c , 12b +13c -15a$and$8a -17b + 4c, 11a -16b + 17c$.

From the sum of$14 a + 9b -8c \ and\ 12b +13c -15a$, we have to subtract the sum of$8a -17b + 4c \ and\ 11a -16b + 17c$.

• By using the Bodmas rule, we are solving the above equation.
• As we know that the Bodmas rule is used to remember the order of operations to be followed while solving expressions in mathematics.

Where,

$\begin{array}{l}\mathrm{B}=\text{brackets}\\\mathrm{O}=\text { order of powers or rules } \\\mathrm{D}=\text { division } \\\mathrm{M}=\text { multiplication } \\\mathrm{A}=\text { addition } \\\mathrm{S}=\text { subtraction }\end{array}$

We are solving in the following way:

We have,

The equations are $14 a + 9b -8c , 12b +13c -15a$and$8a -17b + 4c, 11a -16b + 17c$.

The sum of$14 a + 9b -8c \ and\ 12b +13c -15a$ will be:

$\Rightarrow 14 a + 9b -8c+12b +13c -15a\\\Rightarrow -1a+21b+5c$

The sum of$8a -17b + 4c \ and\ 11a -16b + 17c$ will be:

$\Rightarrow 8a -17b + 4c + 11a -16b + 17c\\\Rightarrow 19a-33b+21c$

Subtracting the sum of$8a -17b + 4c \ and\ 11a -16b + 17c$ from the sum of$14 a + 9b -8c \ and\ 12b +13c -15a$:

$\Rightarrow -1a+21b+5c-(19a-33b+21c)\\\Rightarrow -1a+21b+5c-19a+33b-21c\\\Rightarrow -20a+54b-16c$

Hence, the solution of the above equation is$-20a+54b-16c$.