Question

From the sum of 2 y² + 3yz, - y² -yz - z² and y z+2z², subtract the sum of 3 y² - z² and -y² + y z + z². *​

Answer 1

Step-by-step explanation:

sum of:

(2y²+3yz)+(-y²-yz-z²)+(yz+2z²)

=2y²-y²+3yz-yz+yz+2z²-z²

=y²+3yz+z²

sum of:

(3y²-z²)+(-y²+yz+z²)

=3y²-y²-z²+z²+yz

=2y²+yz

Subtraction

(y²+3yz+z²)–(2y²+yz)

=y²+3yz+z²-2y²-yz

=y²-2y²+3yz-yz+z²

=–y²+2yz+z²

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