Question

From the sum of 2a+13b-4c and 5a-3b+6c, subtract 3a+10b-3c ​

Answer 1

Answer:

$\left(2a+13b-4c\:\right)+\:\left(5a-3b+6c\right)-\:\left(3a+10b-3c)$

$2a+13b-4c+5a-3b+6c-3a-10b+3c$

$(2a+5a-3a)+(13b-10b-3b)+(-4c+6c+3c)$

$(4a+5c)$