Question

from the sum of
2a+3b-5c , 3a-4b and -a+b-c subtract the sum of 2a-b+c , -a+2b+3c and 3b-7c.​

Answer 1

(2a-3b+7c-5a+2b+4c)-(3a+4b-5c)
=-3a-b+11c-3a-4b+5c
=-6a-5b+16c
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Answer 2

Answer:

First, 2a+3b-5c + 3a-4b + -a+b-c = 4a-4c(1)

Now, 2a-b+c + -a+2b+3c +3b-7c =a+3b-3c --------(2)

Now by putting values of 1 and 2 we get

4a-4c - (a+3b-3c)

=4a-4c -a -3b+3c=3a -3b -c

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