Question

From the sum of 2b2 + 3bc , -b2 - bc - bc -c2 and bc + 2c2. Subtract the sum of 3b2 - c2 and -b2 + bc + c2​

Answer 1

Answer:

-b²+bc+c²

Step-by-step explanation:

solve the 1st equation

2b²+3bc + (-b²-bc-bc-c2) + b²+2c²

= 2b²+3bc-b²-2bc-c²+bc+2c²

=b²+2bc+c² ------- (i)

now solve the second equation

3b²-c² + (-b²+bc+c²)

=3b²-c²-b²+bc+c²

=2b²+bc ------ (ii)

now equation (i) - (ii)

b²+2bc+c² - (2b²+bc)

=b²+2bc+c²-2b²-bc

= -b²+bc+c²

hope it helps dear friend

Answer 2

Step-by-step explanation:

hope it helpful too you

please mark me as brainleast