Question

From the sum of 2b2 + 3bc, -b2-bc-c? and bc + 2c2. Subtract the
sum of 3b? - c? and 4a²b - 8ab²​

Answer 1

Firstly, we have to find the sum of 2b² + 3bc, -b²-bc-c

=> (2b²+3bc)+(-b²-bc-c)

=>2b²+3bc-b²-bc-c

=>b²+2bc-c

Now, we have to find the sum of 3b² - c² and 4a²b - 8ab²

=> (3b²-c²)+(4a²b-8ab²)

=>3b²-c²+4a²b-8ab²

Now we add to Subtract the sum of them

=> (b²+2bc-c)-(3b²-c²+4a²b-8ab²)

=>b²+2bc-c-3b²+c²-4a²b+8ab²