from the sum of 2x^2 + 3xy - 5 and 7 +2xy subtract 3xy + x^2 - 2
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1
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Answered by
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Answer:
Sum of the given term is (2x
2
+ 3xy – 5) + (7 + 2xy – x
2
)
= 2x
2
+ 3xy – 5 + 7 + 2xy – x
2
= 2x
2
– x
2
+ 3xy + 2xy – 5 + 7
= x
2
+ 5xy + 2
Now (x
2
+ 5xy + 2) – (3xy + x
2
– 2)
= x
2
+ 5xy + 2 – 3xy – x
2
+ 2
= x
2
– x
2
+ 5xy – 3xy + 2 + 2
= 0 + 2xy + 4
= 2xy + 4
Step-by-step explanation:
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