Math, asked by nishua449, 10 months ago

From the sum of 2x^2+3xy-5 and 7+2xy-x^2 subtract 3xy+x^2-2
Who will tell the answer first and correct I will mark as brainliest ​

Answers

Answered by TooFree
116

Question:

From the sum of 2x² + 3xy - 5 and 7 + 2xy - x²,  subtract 3xy + x² - 2

Solution:

Find the sum of (2x² + 3xy - 5 ) and (7 + 2xy - x²):

(2x² + 3xy - 5 ) + (7 + 2xy - x²)

= 2x² + 3xy - 5  + 7 + 2xy - x²

= x² + 5xy + 2

Subtract 3xy + x² - 2:

(x² + 5xy + 2) - (3xy + x² - 2)

= x² + 5xy + 2 - 3xy - x² + 2

= 2xy + 4

= 2(xy + 2)

Answer:  2(xy + 2)

Answered by s23289
0

Answer:

Question:

From the sum of 2x² + 3xy - 5 and 7 + 2xy - x²,  subtract 3xy + x² - 2

Solution:

Find the sum of (2x² + 3xy - 5 ) and (7 + 2xy - x²):

(2x² + 3xy - 5 ) + (7 + 2xy - x²)

= 2x² + 3xy - 5  + 7 + 2xy - x²

= x² + 5xy + 2

Subtract 3xy + x² - 2:

(x² + 5xy + 2) - (3xy + x² - 2)

= x² + 5xy + 2 - 3xy - x² + 2

= 2xy + 4

= 2(xy + 2)

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