From the sum of 2x^2+3xy-5 and 7+2xy-x^2 subtract 3xy+x^2-2
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Question:
From the sum of 2x² + 3xy - 5 and 7 + 2xy - x², subtract 3xy + x² - 2
Solution:
Find the sum of (2x² + 3xy - 5 ) and (7 + 2xy - x²):
(2x² + 3xy - 5 ) + (7 + 2xy - x²)
= 2x² + 3xy - 5 + 7 + 2xy - x²
= x² + 5xy + 2
Subtract 3xy + x² - 2:
(x² + 5xy + 2) - (3xy + x² - 2)
= x² + 5xy + 2 - 3xy - x² + 2
= 2xy + 4
= 2(xy + 2)
Answer: 2(xy + 2)
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Answer:
Question:
From the sum of 2x² + 3xy - 5 and 7 + 2xy - x², subtract 3xy + x² - 2
Solution:
Find the sum of (2x² + 3xy - 5 ) and (7 + 2xy - x²):
(2x² + 3xy - 5 ) + (7 + 2xy - x²)
= 2x² + 3xy - 5 + 7 + 2xy - x²
= x² + 5xy + 2
Subtract 3xy + x² - 2:
(x² + 5xy + 2) - (3xy + x² - 2)
= x² + 5xy + 2 - 3xy - x² + 2
= 2xy + 4
= 2(xy + 2)
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