From the sum of 2x² + 3xy – 5 and 7 + 2xy – x² subtract 3xy + x² – 2
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2x² + 3xy – 5 + 7 + 2xy – x² - (3xy + x² – 2)
= x² + 5xy + 2 - 3xy - x² + 2
= 2xy + 4
= 2 ( xy + 2 )
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