From the sum of 2x2 + 3xy – 5 and 7 + 2xy – x2 subtract 3xy + x2 – 2.
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Answer:
4x²+2xy
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Answer:
2xy+3
(2x2 +3xy-2) + [7+2xy-2-2]
=>(4+3xy-2)+(7+2xy-4)
=>4+3xy-2+7+2xy-4
=>4-4+3xy+2xy+7-4
=>5xy+3
(5xy+3)-(3xy+2-2)
=>5xy+3-3xy-2+2
=>5xy-3xy+3-2+2
=>2xy+3
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