Question

from the sum of 2x2-4xy+y2 and x2+4xy+y2 subtract x2-4xy+8y2​

Answer 1

${2x}^{2} - 4xy + {y}^{2} \\ {x}^{2} \: \: + 4xy \:+ {y}^{2} \\ {3x}^{2} + 0xy + {2y}^{2} \\ \\ \\ {3x}^{2} + 0xy + {2y}^{2} \\ { - x}^{2} + 4xy { - 8y}^{2} \\ {2x}^{2} + 4xy - {6y}^{2}$

Hence, the answer is

${2x}^{2} + 4xy - {6y}^{2}$

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Answer 2

Answer:

-2x² - 4xy + 6y²

Step-by-step explanation:

= (2x² - 4xy + y²) + (x² + 4xy + y²)

= 3x² + 2y²

= (x² - 4xy + 8y²) - (3x² + 2y²)

= x² - 4xy + 8y² - 3x² - 2y²

= x² - 3x² - 4xy + 8y² - 2y²

= -2x² - 4xy + 6y²

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