Question

From the sum of 2y + 3y2-y-12-2 and yz + 27, subtract the sum of 37 ​

Answer 1

Answer:

y+3y²+yz-24

Step-by-step explanation:

(2y+3y²-y-12-2+y²+27)-37

=(2y-y+3y²+yz-12-2+27)-37

=y+3y²+yz+13-37

=y+3y²+yz-24