from the sum of (2y square +3yz),(_y square Yz _square) and yz +2z square. subtract the sum of 3y square _z square and _y square +yz +z square.
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first question
2y²+3yz
-y² -yz
yz+2z
=y²+(3y+2)z=y²+3yz+2z
3y²-z²
-y² +z²+yz
=2y²+yz
now subtract
y²+3yz+2z-2y²-yz
-y²-2yz+2z
finally answer is y²+2yz-2z
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