Question

From the sum of 2y²+3yz and yz+2z² subtract the sum of 3y²-z² and -

y²+yz+z².​

Answer 1

$\large\underline\purple{\bold{Solution :- }}$

Consider

$\rm :\implies\: ({2y}^{2} + 3yz) + (yz + {2z}^{2} )$

$\rm :\implies\: {2y}^{2} + {2z}^{2} + 4yz$

Now,

Consider

$\rm :\implies\:( {3y}^{2} - {z}^{2} ) + ( {y}^{2} + yz + {z}^{2} )$

$\rm :\implies\: {4y}^{2} + yz$

Now,

Consider,

$\rm :\implies\: {2y}^{2} + {2z}^{2} + 4yz \: - \: ( {4y}^{2} + yz)$

$\rm :\implies\: {2y}^{2} + {2z}^{2} + 4yz \: - {4y}^{2} - yz$

$\rm :\implies\: {2z}^{2} + {2y}^{2} + 3yz$

Answer 2

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Step-by-step explanation:

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