Math, asked by bved007, 3 months ago

From the sum of 2y2 + 3yz, – y

2 – yz – z

2 and yz + 2z2, subtract the sum of 3y2 – z

2 and

–y

2 + 2 yz + z . ​

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Answers

Answered by tennetiraj86
7

Answer:

answer for the given problem is given

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Answered by avni9050
3

Answer:

z² - z + yz

Step-by-step explanation:

(2y² + 3yz - y² - yz - z² + yz + 2z² ) - (3y² - z² - y² + 2yz + z)

(y² + z² + 3yz ) - ( 2y² + 2yz - y² + z)

y² + z² + 3yz - 2y² - 2yz + y² - z

z² - z + yz

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