Question

From the sum of 2y2 + 3yz, - y - yz - z- and yz + 2z2, subtract the sum of 3y2 2?
and - y2 + y2 + z2​

Answer 1

Sum A= {y}^{2} + 2yz + {z}^{2} y 2 +2yz+z 2

Sum B=2 {y}^{2} + yz 2y 2 +yz

Therefore difference of Sum A and B,

\begin{gathered} {y}^{2} + 2yz + {z}^{2} - (2 {y}^{2} + yz) \\ {y}^{2} + 2yz + {z}^{2} - 2 {y}^{2} - yz \\ - {y }^{2} + yz + {z}^{2} \end{gathered} y 2 +2yz+z 2 −(2y 2 +yz)y 2 +2yz+z 2 −2y 2−yz−y 2 +yz+z 2

Hope it helped...

Answer 2

$\Huge\boxed {-y²+yz+z²}$

⚫sum of 2y2 + 3yz, - y - yz - z- and yz + 2z2, subtract the sum of 3y2 2 and - y2 + y2 + z2 is -y² + yz + z²