Question

From the sum of 2y2 + 3yz, -y2 - y2 – 22 and yz + 2z2, subtract the sum of
3y2– 22 and - y2 +y2 +22​ pls answer

Answer 1

Answer:

4yz - 22 + 2z^2 - 3y^2

Step-by-step explanation:

(2y^2 + 3yz - y^2 - y^2 - 22 + yz + 2z^2)-(3y^2 -22 - y^2 + y^2 + 22)

= 2y^2 + 3yz - y^2 - y^2 - 22 + yz + 2z^2 - 3y^2 + 22 + y^2 - y^2 - 22

= 4yz - 22 + 2z^2 - 3y^2

Answer 2

Answer:

From the sum of 2y2+3yz,-y

2

-yz-z

2

and yz+2z2

, subtract the sum of 3y2+z2 and –y

2+yz+z2Subtract 24ab-10b-18a from 30ab+12b+14a.PQRS is a parallelogram. QM is the height from Q to SR and QN is the height from QQ

to PS. If SR= 12cm and QM= 7.6cm, find

a) The area of the parallelogram PQRS

b) QN, If PS= 8cmThe radius of a circular pipe is 10cm. What length of a tape is required to wrap once

around the pipe (π= 3.14)