Question

From the sum of 2y2 + 3yz , -y2 -yz + 2z2 subtract the sum of 3y2 –

z2 and -y2 + yz + 2z ....
pls answer....​

Answer 1

Answer:

sorry I didn't get to talk in the following weekend is the

Answer 2

Answer:

the answer is

Step-by-step explanation:

Sum of 2y

2

+3yz,−y

2

−yz−z

2

and yz−2z

2

=2y

2

+3yz−y

2

−yz−z

2

+yz+2z

2

=y

2

+z

2

+3yz

and sum =3y

2

−z

2

,(−y

2

+yz+z

2

)

=3y

2

−z

2

−y

2

+yz+z

2

=2y

2

+yz

Now,(y

2

+z

2

+3yz)−(2y

2

+yz)

=y

2

+z

2

+3yz−2y

2

−yz

−y

2

+z

2

+2yz

−y

2

+2yz+z

2