Math, asked by dhatrigupta, 3 months ago

From the sum of 2y² + 3yz , -y² -yz + 2z² subtract the sum of 3y² – z² and -y² + yz

Answers

Answered by BoldStyle
8

3y² - - + yz - ( 2y² + 3yz - - yz + 2z² )

2y² + yz - - ( + 2yz + 2z² )

2y² + yz - - - 2yz - 2z²

Answer - yz - 3z²

Answered by Anonymous
0

Answer:

the answer is y2 - yz -3z2

Step-by-step explanation:

hope it helps you

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