Question

From the sum of 2y² + 3yz , -y² -yz + 2z² subtract the sum of 3y² – z² and -y² + yz

Answer 1

3y² - z² - y² + yz - ( 2y² + 3yz - y² - yz + 2z² )

2y² + yz - z² - ( y² + 2yz + 2z² )

2y² + yz - z² - y² - 2yz - 2z²

Answer ➡ y² - yz - 3z²

Answer 2

Answer:

the answer is y2 - yz -3z2

Step-by-step explanation:

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