Question

From the sum of 2y2 + 3yz, -y2 -yz -z2 and yz+ 2z2, subtract the sum of 3y2 - z2 and -y2 + yz + z2.

Answer 1

Answer:

The sum of 2y2 + 3yz, -y2 -z2 and yz + 2z2 is y2+3yz+z2

The sum of 3y3 -z2 and -y2 + yz + z2 is 2y2+yz

And when we subtract 2y2 +yz from y2 + 3yz + z2

Here sign will be change

y2 + 3yz +z2

2y2 + yz + 0

- - -

-y2 +yz +z2 Ans

Hope it will help you and you will understand it coz it is not written so much clear and plz mark me as the brainiest plz

Answer 2

hii

given

⟼From the sum of 2y2 + 3yz, -y2 -yz -z2 and yz+ 2z2, subtract the sum of 3y2 - z2 and -y2 + yz + z2.

to find

• From the sum .
• subscract the sum.

answer

⟼$- y {}^{2} + yz + z {}^{2}$

solusion

⟼see in attachment

hope it's helps you