Question

from the sum of 2y2+3yz,-y2-yz-z2 and yz+2z2, subtract the sum of 3y2-z2 and -y2+yz+z2

Answer 1

Sum A=
${y}^{2} + 2yz + {z}^{2}$
Sum B=
$2 {y}^{2} + yz$
Therefore difference of Sum A and B,

${y}^{2} + 2yz + {z}^{2} - (2 {y}^{2} + yz) \\ {y}^{2} + 2yz + {z}^{2} - 2 {y}^{2} - yz \\ - {y }^{2} + yz + {z}^{2}$
Hope it helped...

pls mark brainliest

Answer 2

Answer:

Sum A=

{y}^{2} + 2yz + {z}^{2}y

2

+2yz+z

2

Sum B=

2 {y}^{2} + yz2y

2

+yz

Therefore difference of Sum A and B,

\begin{gathered} {y}^{2} + 2yz + {z}^{2} - (2 {y}^{2} + yz) \\ {y}^{2} + 2yz + {z}^{2} - 2 {y}^{2} - yz \\ - {y }^{2} + yz + {z}^{2} \end{gathered}

y

2

+2yz+z

2

−(2y

2

+yz)

y

2

+2yz+z

2

−2y

2

−yz

−y

2

+yz+z

2

Hope it helped...

pls mark brainliest