From the sum of 3 − + 11 and− − 11 subtract3 − − 11.
Answers
Answered by
1
Answer:
We need to find the sum of 3x-y+11 and -y-11, subtract 3x-y-11.
sum of 3x-y+11 and -y-11 is
(3x-y+11)+(-y-11)(3x−y+11)+(−y−11)
3x-y+11-y-113x−y+11−y−11
Combine like terms.
3x+(-y-y)+(11-11)3x+(−y−y)+(11−11)
3x-2y3x−2y
Now subtract 3x-y-11 from 3x-2y.
3x-2y-(3x-y-11)3x−2y−(3x−y−11)
3x-2y-3x+y+113x−2y−3x+y+11
Combine like terms.
(3x-3x)+(-2y+y)+11(3x−3x)+(−2y+y)+11
-y+11−y+11
Therefore, the required expression is -y+11.
#Learn more
Simplify the following:
(2x + 5y)² + (2x - 5y)square
Answered by
0
Answer:
3 -( + 11 ) = 3 - 11 = -8
3 - ( - 11 ) = 3 + 11 = 14
Similar questions