Math, asked by uma9588, 1 month ago

From the sum of 3 − + 11 and− − 11 subtract3 − − 11.

Answers

Answered by Anonymous
1

Answer:

We need to find the sum of 3x-y+11 and -y-11, subtract 3x-y-11.

sum of 3x-y+11 and -y-11 is

(3x-y+11)+(-y-11)(3x−y+11)+(−y−11)

3x-y+11-y-113x−y+11−y−11

Combine like terms.

3x+(-y-y)+(11-11)3x+(−y−y)+(11−11)

3x-2y3x−2y

Now subtract 3x-y-11 from 3x-2y.

3x-2y-(3x-y-11)3x−2y−(3x−y−11)

3x-2y-3x+y+113x−2y−3x+y+11

Combine like terms.

(3x-3x)+(-2y+y)+11(3x−3x)+(−2y+y)+11

-y+11−y+11

Therefore, the required expression is -y+11.

#Learn more

Simplify the following:

(2x + 5y)² + (2x - 5y)square

Answered by dhivakar8892
0

Answer:

3 -( + 11 ) = 3 - 11 = -8

3 - ( - 11 ) = 3 + 11 = 14

Similar questions