Question

From the sum of-3/4 and 2/5, subtract 5/6 .​

Answer 1

★ How to do :-

Here, we are given with three fractions in which we are asked to find the sum of two fractional numbers and we should subtract ⅚ from it. So, first we should find the sum of those two fractions given at first in the bracket. So, after finding the sum of those fractions, we should subtract the other fraction from the sum of those fractions. So, here we are going to use the concepts of LCM i.e, the least common multiple. So, let's solve!!

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➤ Solution :-

${\tt \leadsto \bigg( \dfrac{(-3)}{4} + \dfrac{2}{5} \bigg) - \dfrac{5}{6}}$

First, solve the given bracket.

${\tt \leadsto \dfrac{(-3)}{4} + \dfrac{2}{5}}$

Convert them into like fractions by taking the LCM of the denominators i.e, 4 and 5.

LCM of 4 and 5 is 20.

${\tt \leadsto \dfrac{(-3) \times 5}{4 \times 5} + \dfrac{2 \times 4}{5 \times 4}}$

Multiply the numerators and denominators of both fractions and write both numerators in one farction.

${\tt \leadsto \dfrac{(-15)}{20} + \dfrac{8}{20} = \dfrac{(-15) + 8}{20}}$

Add the numbers in the numerator.

${\tt \leadsto \dfrac{(-7)}{20}}$

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Now, subtract the obtained answer with other fraction given in the question.

${\tt \leadsto \dfrac{(-7)}{20} - \dfrac{5}{6}}$

Convert them into like fractions by taking the LCM of the denominators i.e, 20 and 6.

LCM of 20 and 6 is 60.

${\tt \leadsto \dfrac{(-7) \times 3}{20 \times 3} - \dfrac{5 \times 10}{6 \times 10}}$

Multiply the numerators and denominators of both fractions and write both numerators in one fraction.

${\tt \leadsto \dfrac{(-21)}{60} - \dfrac{50}{60} = \dfrac{(-21) - 50}{60}}$

Subtract to get the final answer.

${\tt \leadsto \pink{\underline{\boxed{\tt \dfrac{(-71)}{60}}}}}$

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Hence solved !!