Question

From the sum of 3 x - y + 11 and - y -11 , subtract 2 x – 3y + 11.​

Answer 1

${\blue{\huge{\tt{\underline{\underline{Question}}}}}}$

From the sum of 3 x - y + 11 and - y -11 , subtract 2 x – 3y + 11.

${\blue{\huge{\tt{\underline{\underline{Solution}}}}}}$

Sum (Addition)

= 3x - y + 11 + (-y -11)

= 3x - y + 11 - y -11

= 3x -y - y + 11 - 11

= 3x - 2y + 0

= 3x - 2y

Subtracting 2x - 3y + 11 from Above sum

3x - 2y - (2x - 3y + 11)

= 3x - 2y - 2x + 3y - 11

= 3x - 2x - 2y + 3y -11

= x + y -11

$\boxed{\green{\therefore Answer\ is\ x + y -11}}$

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Answer 2

Answer:

Question

From the sum of 3 x - y + 11 and - y -11 , subtract 2 x – 3y + 11.

Solution

Sum (Addition)

= 3x - y + 11 + (-y -11)

= 3x - y + 11 - y -11

= 3x -y - y + 11 - 11

= 3x - 2y + 0

= 3x - 2y

Subtracting 2x - 3y + 11 from Above sum

3x - 2y - (2x - 3y + 11)

= 3x - 2y - 2x + 3y - 11

= 3x - 2x - 2y + 3y -11

= x + y -11

∴Answer is x+y−11