Math, asked by jawarawalaimran, 9 months ago

From the sum of: -3ab+6b²+17c² and 3c²-16b²- ¼ ab subtract the sum of -⅓b² + c²-7ab and 2/7b²+ ⅕c²- 2ab.​

Answers

Answered by himeshchoudhary915
0

Answer:

From the sum of: -3ab+6b²+17c² and 3c²-16b²- ¼ ab subtract the sum of -⅓b² + c²-7ab and 2/7b²+ ⅕c²- 2ab.

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