from the sum of 3p²+2q²;-p²-4q²+2pq and 6pq+2p²-3q² subtract -3p²+2q²-3pq.
plZ
Answers
Answered by
1
Answer:
p square, 5qsquare, 5 pa
Answered by
0
No the above answer is wrong therefore the solution
Sum=(3-1+6)p^2+(2-4+2)q^2+(0+2)part = 4 p^2+2pq
From this subraction = (3+3)p^2 +(2-2)q^2 +(0-2)pq
=6p^2-2pq
Sum=(3-1+6)p^2+(2-4+2)q^2+(0+2)part = 4 p^2+2pq
From this subraction = (3+3)p^2 +(2-2)q^2 +(0-2)pq
=6p^2-2pq
Similar questions