From the sum of 3x-2y+4z and 3y-2z,subtract x-y-z
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Step-by-step explanation:
(3x-2y+4z)+(3y-2z)
=3x-2y+3y+4z-2z
=3x+y+2z
now,
( 3x+y+2z )-(x-y-z)
=3x+y+2z-x+y+z
=3x-x+y+y+2z+z
=2x+2y+3z
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