from the sum of 3x-y+11 subtract -y-11 subtract 5x-2y+11
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Answer:
Sum of 3x−2y+7 and 5x−3y−8
=3x−2y+7+5x−3y−8
=8x−5y−1
Thus, 8x−5y−1−(4x+y+2)
=8x−5y−1−4x−y−2
=4x−6y−3
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