Question

From the sum of 4+3x+2y and 2y+3x+6 subtract x+2y​

Answer 1

Answer:

The value of terms as per the question is calculated as follows

(3x−y+z)+(x+y−3z)−(x−2y−z)

=3x+x−x−y+y+2y+z−3z+z

We get,

=3x+2y−z

Therefore, (3x−y+z)+(x+y−3z)−(x−2y−z)=3x+2y−z

Step-by-step explanation:

Answer 2

Answer:

10+5x+2y

Step-by-step explanation:

(4+6) + (3x+3x) + (2y+2y)

10 + 6x + 4y

• 10 + (6x-x) + (4y-2y)

= 10+5x+2y