Question

From the sum of (4+3x) and (5-4x + 2x^2) subtract the sum of (3x^2 -- 5x)and (x^2+2x+5)​

Answer 1

Answer:

$4 + 3x + 5 - 4x + 2 {x}^{2} \\ = 2 {x}^{2} - x + 9$

$3 {x}^{2} - 5x + {x}^{2} + 2x + 5 \\ = 4 {x}^{2} - 3x + 5$

$2 {x}^{2} - x + 9 - (4 {x}^{2} - 3x + 5 \\ = 2 {x}^{2} - x + 9 - 4 {x}^{2} + 3x - 5 \\ = - 2 {x}^{2} + 2 x+ 4 \\or \\ = 2 ({x}^{2} - x - 2)$

Answer 2

$\huge \blue{ 4 + 3x + 5 - 4x - 2 {x}^{2} }$

$\huge \green{ = 2 {x}^{2} - x + 9}$

$\huge \red{3 {x}^{2} - 5x + {x}^{2} + 2x + 5}$

$\huge{ = 4 {x}^{2} - 3x + 5}$

$\huge \red{2 {x}^{2} - x + 9 - 4 {x}^{2} - 3x + 5 }$

$\huge \blue{ = - 2 {x}^{2} +2x + 4 }$

$\huge \green{ = - 2( {x}^{2} - x - 2)}$

hope it's my answer