Question

From the sum of 4 + 3x and 5 - 4x + 2x sq., subtract the sum of 3x sq. - 5x and - x sq. + 2x + 5.

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Answer 1

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Answer 2

Answer: (0x^2 - 4x + 14) or ( - 4x + 14)

Step-by-step explanation:

Solution -

(4 + 3x) + (5 - 4x + 2x^2)

= 4 + 3x + 5 - 4x + 2x^2

= 4 + 5 + 3x - 4x + 2x^2

= 9 - x + 2x^2

= 2x^2 - x +9 ( 1 )

(3x^2 - 5x) + (-x^2 + 2x + 5)

= 3x^2 - 5x - x^2 + 2x + 5

= 3x^2 - x^2 - 5x + 2x + 5

= 2x^2 - 3x + 5 ( 2 )

Now subject eqn. ( 2 ) from eqn. ( 1 ).

(2x^2 - x +9) - (2x^2 - 3x + 5)

= 2x^2 - x +9 - 2x^2 - 3x + 5

= 2x^2 - 2x^2 - x - 3x + 9 + 5

= 0x^2 - 4x + 14 or - 4x + 14

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