Question

From the sum of 4 + 3x and 5 – 4x + 2x2
, subtract the sum of
3x2
– 5x and -x2
+ 2x + 5.

Answer 1

From the given question the correct answer is:

the Answer of the given question is 4+2x.

Given:

the sum of

4+3x and 5-4x+2x²

subtract the sum of

3x²-5x and -x²+2x+5

Solution:

4+3x-------------(1)

5-4x+2x²----------(2)

add the eqaution 1 and 2

 4+3x

+5-4x+2x²

 9-x+2x² -----------(3)

Now,

3x²-5x ---------(4)

-x²+2x+5-------(5)

Add the equation 4 and 5

3x²-5x

 -x²+2x+5

2x²-3x+5 ------------(6)

Now subtract equation 6 from equation 3

we get ,

=  9-x+2x² - 2x²-3x+5

=4+2x

Hence, the Answer of the given question is 4+2x.

Answer 2

Answer:

To find :  from sum of $4 + 3x$  and $5 - 4x + 2x^{2}$ we have to  subtract the sum of   $3x^{2} - 5x$ and $- x^{2} + 2x + 5$

finding the sum of $4 + 3x$  and $5 - 4x + 2x^{2}$

( $4 + 3x$ ) + ( $5 - 4x + 2x^{2}$ )

$4 + 3x$ + $5 - 4x + 2x^{2}$

= $9 - x + 2x^{2}$

rearranging answer in standard form : $2x^{2} - x + 9$ ----------------(i)

finding the sum of $3x^{2} - 5x$ and $- x^{2} + 2x + 5$

(  $3x^{2} - 5x$ ) + ( $- x^{2} + 2x + 5$ )

$3x^{2} - 5x$ $- x^{2} + 2x + 5$

= $2x^{2} - 3x + 5$            -------------------------(ii)

subtracting eq (ii) from (i) we get,

( $2x^{2} - x + 9$ ) - ( $2x^{2} - 3x + 5$ )

= $2x^{2} - x + 9$ - $2x^{2} + 3x - 5$

= $2x + 4$

hence difference comes out to be $2x + 4$ .